Page 163 - Maths Class 04

So, perimeter = 9 + 3 + 3 + 2 + 3 + 3 + 9 + 3 + 3 + 2 + 3 + 3
= 46 m

So, the total cost = 46 × ` 150 = ` 6900

It will cost ` 6900 for fencing the park.

Example : The edges of a bed sheet that
is 4 m long and 3 m wide must

be stitched with lace. How

much lace is needed ?
Solution : To find the answer we will find

the perimeter of the bed sheet.

P = 2 × (length + breadth)
= 2 × (4 + 3)

= 2 ×7

= 14 m
So, 14 m lace is required for the bed sheet.

Practice - 11.4
Practice - 11.4
Practice - 11.4
Practice - 11.4
1. The length and breadth of a rectangular park are 150 m and 120 m
respectively. Find the length of wire needed to fence all around the park 2 times.

2. A square park is 140 metres long. How much wire will be needed for fencing
around it two times ?

3. The length and breadth of a rectangular playground are 120 metres and 80
metres respectively. What distance will a boy cover walking around the

playground three times ?

4. A square shaped bed of flower has to be fenced. If a side of the bed is 60 m
long. What will be the length of the fence ?

5. How much fencing will be needed for a triangular garden whose sides are of

the lengths 15 , 20 and 25 ?m m m
6. The playground in front of a school was 32 m long and 18 m broad. Find the

perimeter of the playground .

7. Mr Jha was planning to build a new room. The room was 20 m long and 18 m
broad. Find the perimeter of the room.

Mathematics-4 163